3.1811 \(\int \frac{1}{\sqrt [6]{a+b x} (c+d x)^{29/6}} \, dx\)

Optimal. Leaf size=136 \[ \frac{7776 b^3 (a+b x)^{5/6}}{21505 (c+d x)^{5/6} (b c-a d)^4}+\frac{1296 b^2 (a+b x)^{5/6}}{4301 (c+d x)^{11/6} (b c-a d)^3}+\frac{108 b (a+b x)^{5/6}}{391 (c+d x)^{17/6} (b c-a d)^2}+\frac{6 (a+b x)^{5/6}}{23 (c+d x)^{23/6} (b c-a d)} \]

[Out]

(6*(a + b*x)^(5/6))/(23*(b*c - a*d)*(c + d*x)^(23/6)) + (108*b*(a + b*x)^(5/6))/(391*(b*c - a*d)^2*(c + d*x)^(
17/6)) + (1296*b^2*(a + b*x)^(5/6))/(4301*(b*c - a*d)^3*(c + d*x)^(11/6)) + (7776*b^3*(a + b*x)^(5/6))/(21505*
(b*c - a*d)^4*(c + d*x)^(5/6))

________________________________________________________________________________________

Rubi [A]  time = 0.0301452, antiderivative size = 136, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 2, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.105, Rules used = {45, 37} \[ \frac{7776 b^3 (a+b x)^{5/6}}{21505 (c+d x)^{5/6} (b c-a d)^4}+\frac{1296 b^2 (a+b x)^{5/6}}{4301 (c+d x)^{11/6} (b c-a d)^3}+\frac{108 b (a+b x)^{5/6}}{391 (c+d x)^{17/6} (b c-a d)^2}+\frac{6 (a+b x)^{5/6}}{23 (c+d x)^{23/6} (b c-a d)} \]

Antiderivative was successfully verified.

[In]

Int[1/((a + b*x)^(1/6)*(c + d*x)^(29/6)),x]

[Out]

(6*(a + b*x)^(5/6))/(23*(b*c - a*d)*(c + d*x)^(23/6)) + (108*b*(a + b*x)^(5/6))/(391*(b*c - a*d)^2*(c + d*x)^(
17/6)) + (1296*b^2*(a + b*x)^(5/6))/(4301*(b*c - a*d)^3*(c + d*x)^(11/6)) + (7776*b^3*(a + b*x)^(5/6))/(21505*
(b*c - a*d)^4*(c + d*x)^(5/6))

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*Simplify[m + n + 2])/((b*c - a*d)*(m + 1)), Int[(a + b*x)^Simplify[m +
1]*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[Simplify[m + n + 2], 0] &&
 NeQ[m, -1] &&  !(LtQ[m, -1] && LtQ[n, -1] && (EqQ[a, 0] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && (
SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n +
1))/((b*c - a*d)*(m + 1)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rubi steps

\begin{align*} \int \frac{1}{\sqrt [6]{a+b x} (c+d x)^{29/6}} \, dx &=\frac{6 (a+b x)^{5/6}}{23 (b c-a d) (c+d x)^{23/6}}+\frac{(18 b) \int \frac{1}{\sqrt [6]{a+b x} (c+d x)^{23/6}} \, dx}{23 (b c-a d)}\\ &=\frac{6 (a+b x)^{5/6}}{23 (b c-a d) (c+d x)^{23/6}}+\frac{108 b (a+b x)^{5/6}}{391 (b c-a d)^2 (c+d x)^{17/6}}+\frac{\left (216 b^2\right ) \int \frac{1}{\sqrt [6]{a+b x} (c+d x)^{17/6}} \, dx}{391 (b c-a d)^2}\\ &=\frac{6 (a+b x)^{5/6}}{23 (b c-a d) (c+d x)^{23/6}}+\frac{108 b (a+b x)^{5/6}}{391 (b c-a d)^2 (c+d x)^{17/6}}+\frac{1296 b^2 (a+b x)^{5/6}}{4301 (b c-a d)^3 (c+d x)^{11/6}}+\frac{\left (1296 b^3\right ) \int \frac{1}{\sqrt [6]{a+b x} (c+d x)^{11/6}} \, dx}{4301 (b c-a d)^3}\\ &=\frac{6 (a+b x)^{5/6}}{23 (b c-a d) (c+d x)^{23/6}}+\frac{108 b (a+b x)^{5/6}}{391 (b c-a d)^2 (c+d x)^{17/6}}+\frac{1296 b^2 (a+b x)^{5/6}}{4301 (b c-a d)^3 (c+d x)^{11/6}}+\frac{7776 b^3 (a+b x)^{5/6}}{21505 (b c-a d)^4 (c+d x)^{5/6}}\\ \end{align*}

Mathematica [A]  time = 0.0508207, size = 118, normalized size = 0.87 \[ \frac{6 (a+b x)^{5/6} \left (165 a^2 b d^2 (23 c+6 d x)-935 a^3 d^3-15 a b^2 d \left (391 c^2+276 c d x+72 d^2 x^2\right )+b^3 \left (7038 c^2 d x+4301 c^3+4968 c d^2 x^2+1296 d^3 x^3\right )\right )}{21505 (c+d x)^{23/6} (b c-a d)^4} \]

Antiderivative was successfully verified.

[In]

Integrate[1/((a + b*x)^(1/6)*(c + d*x)^(29/6)),x]

[Out]

(6*(a + b*x)^(5/6)*(-935*a^3*d^3 + 165*a^2*b*d^2*(23*c + 6*d*x) - 15*a*b^2*d*(391*c^2 + 276*c*d*x + 72*d^2*x^2
) + b^3*(4301*c^3 + 7038*c^2*d*x + 4968*c*d^2*x^2 + 1296*d^3*x^3)))/(21505*(b*c - a*d)^4*(c + d*x)^(23/6))

________________________________________________________________________________________

Maple [A]  time = 0.007, size = 171, normalized size = 1.3 \begin{align*} -{\frac{-7776\,{x}^{3}{b}^{3}{d}^{3}+6480\,a{b}^{2}{d}^{3}{x}^{2}-29808\,{b}^{3}c{d}^{2}{x}^{2}-5940\,{a}^{2}b{d}^{3}x+24840\,a{b}^{2}c{d}^{2}x-42228\,{b}^{3}{c}^{2}dx+5610\,{a}^{3}{d}^{3}-22770\,{a}^{2}cb{d}^{2}+35190\,a{b}^{2}{c}^{2}d-25806\,{b}^{3}{c}^{3}}{21505\,{a}^{4}{d}^{4}-86020\,{a}^{3}bc{d}^{3}+129030\,{a}^{2}{c}^{2}{b}^{2}{d}^{2}-86020\,a{b}^{3}{c}^{3}d+21505\,{b}^{4}{c}^{4}} \left ( bx+a \right ) ^{{\frac{5}{6}}} \left ( dx+c \right ) ^{-{\frac{23}{6}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x+a)^(1/6)/(d*x+c)^(29/6),x)

[Out]

-6/21505*(b*x+a)^(5/6)*(-1296*b^3*d^3*x^3+1080*a*b^2*d^3*x^2-4968*b^3*c*d^2*x^2-990*a^2*b*d^3*x+4140*a*b^2*c*d
^2*x-7038*b^3*c^2*d*x+935*a^3*d^3-3795*a^2*b*c*d^2+5865*a*b^2*c^2*d-4301*b^3*c^3)/(d*x+c)^(23/6)/(a^4*d^4-4*a^
3*b*c*d^3+6*a^2*b^2*c^2*d^2-4*a*b^3*c^3*d+b^4*c^4)

________________________________________________________________________________________

Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x + a\right )}^{\frac{1}{6}}{\left (d x + c\right )}^{\frac{29}{6}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a)^(1/6)/(d*x+c)^(29/6),x, algorithm="maxima")

[Out]

integrate(1/((b*x + a)^(1/6)*(d*x + c)^(29/6)), x)

________________________________________________________________________________________

Fricas [B]  time = 1.91764, size = 883, normalized size = 6.49 \begin{align*} \frac{6 \,{\left (1296 \, b^{3} d^{3} x^{3} + 4301 \, b^{3} c^{3} - 5865 \, a b^{2} c^{2} d + 3795 \, a^{2} b c d^{2} - 935 \, a^{3} d^{3} + 216 \,{\left (23 \, b^{3} c d^{2} - 5 \, a b^{2} d^{3}\right )} x^{2} + 18 \,{\left (391 \, b^{3} c^{2} d - 230 \, a b^{2} c d^{2} + 55 \, a^{2} b d^{3}\right )} x\right )}{\left (b x + a\right )}^{\frac{5}{6}}{\left (d x + c\right )}^{\frac{1}{6}}}{21505 \,{\left (b^{4} c^{8} - 4 \, a b^{3} c^{7} d + 6 \, a^{2} b^{2} c^{6} d^{2} - 4 \, a^{3} b c^{5} d^{3} + a^{4} c^{4} d^{4} +{\left (b^{4} c^{4} d^{4} - 4 \, a b^{3} c^{3} d^{5} + 6 \, a^{2} b^{2} c^{2} d^{6} - 4 \, a^{3} b c d^{7} + a^{4} d^{8}\right )} x^{4} + 4 \,{\left (b^{4} c^{5} d^{3} - 4 \, a b^{3} c^{4} d^{4} + 6 \, a^{2} b^{2} c^{3} d^{5} - 4 \, a^{3} b c^{2} d^{6} + a^{4} c d^{7}\right )} x^{3} + 6 \,{\left (b^{4} c^{6} d^{2} - 4 \, a b^{3} c^{5} d^{3} + 6 \, a^{2} b^{2} c^{4} d^{4} - 4 \, a^{3} b c^{3} d^{5} + a^{4} c^{2} d^{6}\right )} x^{2} + 4 \,{\left (b^{4} c^{7} d - 4 \, a b^{3} c^{6} d^{2} + 6 \, a^{2} b^{2} c^{5} d^{3} - 4 \, a^{3} b c^{4} d^{4} + a^{4} c^{3} d^{5}\right )} x\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a)^(1/6)/(d*x+c)^(29/6),x, algorithm="fricas")

[Out]

6/21505*(1296*b^3*d^3*x^3 + 4301*b^3*c^3 - 5865*a*b^2*c^2*d + 3795*a^2*b*c*d^2 - 935*a^3*d^3 + 216*(23*b^3*c*d
^2 - 5*a*b^2*d^3)*x^2 + 18*(391*b^3*c^2*d - 230*a*b^2*c*d^2 + 55*a^2*b*d^3)*x)*(b*x + a)^(5/6)*(d*x + c)^(1/6)
/(b^4*c^8 - 4*a*b^3*c^7*d + 6*a^2*b^2*c^6*d^2 - 4*a^3*b*c^5*d^3 + a^4*c^4*d^4 + (b^4*c^4*d^4 - 4*a*b^3*c^3*d^5
 + 6*a^2*b^2*c^2*d^6 - 4*a^3*b*c*d^7 + a^4*d^8)*x^4 + 4*(b^4*c^5*d^3 - 4*a*b^3*c^4*d^4 + 6*a^2*b^2*c^3*d^5 - 4
*a^3*b*c^2*d^6 + a^4*c*d^7)*x^3 + 6*(b^4*c^6*d^2 - 4*a*b^3*c^5*d^3 + 6*a^2*b^2*c^4*d^4 - 4*a^3*b*c^3*d^5 + a^4
*c^2*d^6)*x^2 + 4*(b^4*c^7*d - 4*a*b^3*c^6*d^2 + 6*a^2*b^2*c^5*d^3 - 4*a^3*b*c^4*d^4 + a^4*c^3*d^5)*x)

________________________________________________________________________________________

Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a)**(1/6)/(d*x+c)**(29/6),x)

[Out]

Timed out

________________________________________________________________________________________

Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x + a\right )}^{\frac{1}{6}}{\left (d x + c\right )}^{\frac{29}{6}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a)^(1/6)/(d*x+c)^(29/6),x, algorithm="giac")

[Out]

integrate(1/((b*x + a)^(1/6)*(d*x + c)^(29/6)), x)